0=2(x^2-2x+520)

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Solution for 0=2(x^2-2x+520) equation: 



0=2(x^2-2x+520)

We move all terms to the left:

0-(2(x^2-2x+520))=0

We add all the numbers together, and all the variables

-(2(x^2-2x+520))=0



We calculate terms in parentheses: -(2(x^2-2x+520)), so:

2(x^2-2x+520)

We multiply parentheses

2x^2-4x+1040

Back to the equation:

-(2x^2-4x+1040)



We get rid of parentheses

-2x^2+4x-1040=0

a = -2; b = 4; c = -1040;
Δ = b2-4ac
Δ = 42-4·(-2)·(-1040)
Δ = -8304
Delta is less than zero, so there is no solution for the equation

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